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razor99 (razor99):
i think its C maybe lol
OpenStudy (bohotness):
can soemone help you confrit that?
jimthompson5910 (jim_thompson5910):
Add up the heights of each bar to figure out how many students there are. Call this number x
Then add up the heights of the bars for fri and sat. Call this number y
divide the two (y/x) and reduce that fraction as much as possible
OpenStudy (bohotness):
O.Ow
razor99 (razor99):
lol that reaction tho
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jimthompson5910 (jim_thompson5910):
Add up the heights of each bar. What do you get?
OpenStudy (ybarrap):
The probability you need is:
$$
{\text{# in Fri}+\text{# in Sat}} \over {\sum \text{in all days}}
$$
OpenStudy (anonymous):
Ybarrap has the correct equation
use it to find the probability
the answer should be c as initially answered
OpenStudy (bohotness):
lol ikr i am sorry confused
OpenStudy (bohotness):
lag :( anyway wait what? O.OO.o
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OpenStudy (anonymous):
oh and jim thompson provided the correct explanation
OpenStudy (bohotness):
okay but which bar?
OpenStudy (anonymous):
Okay so let me summarized what they said
How many students in the class? Find that by adding up the tally for each days.
OpenStudy (bohotness):
27
OpenStudy (anonymous):
Check again, provide the numbers for each day this time
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OpenStudy (bohotness):
26?
OpenStudy (anonymous):
Sorry some glitch in the site
OpenStudy (anonymous):
Anyway yes it's 26
Now according to the fine gentlemen who answered your question before
Add up the numbers for friday and saturday
what do you get?
OpenStudy (bohotness):
okay
OpenStudy (bohotness):
thanks xd
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OpenStudy (anonymous):
lol did you even get your answer? Clearly we haven't got to that yet
OpenStudy (bohotness):
yes
OpenStudy (anonymous):
so your answer is....
OpenStudy (bohotness):
carp it changed
OpenStudy (anonymous):
oh
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