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where is the orthocenter of obtuse triangle cde located? find gd a. outside of triangle, gd = 5 b. inside the triangle, gd = 5 c. outside the triangle, gd = 7 d. inside the triangle, gd = 7
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WILL GIVE MEDAL PLZZZ HELP QUICK!!
We know that EGC is the supplementary angle of CGD, so: $$ \angle EGC = 180^\circ - \angle CGD = 180^\circ 90^\circ = 90^\circ $$But we are also told that: $$ EGC = (5x + 55)^\circ $$So we can say: $$ (5x + 55)^\circ = 90^\circ \\ 5x + 55= 90\\ 5x = 90 - 55 = 35\\ x = \frac{35}{5} = 7 $$So: $$ GD = 2x - 9 = 2 \cdot 7 - 9 = 14 - 9 = 5 $$
Also, for obtuse triangles the orthocenter will be outside the triangle: http://www.mathopenref.com/triangleorthocenter.html
ty!!
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