If a pea plant is heterozygous for round and yellow (RrYy) is crossed with a pea plant that is homozygous for round but heterozygous for yellow (RRYy), how many different phenotypes are possible for their offspring?
a. 2
b. 4
c. 8
d. 16

Question

If a pea plant is heterozygous for round and yellow (RrYy) is crossed with a pea plant that is homozygous for round but heterozygous for yellow (RRYy), how many different phenotypes are possible for their offspring? 
a. 2
b. 4
c. 8
d. 16

anonymous · Answer

what do you think?

anonymous · Answer

I was thinking of 4.

unanimoose · Answer

The answer lies within your heart.

anonymous · Answer

Okay, but I can't just reach into my heart and get it. ;-)

anonymous · Answer

It's not 4.

anonymous · Answer

I know how to explain this, but it's a long explanation. Much easier if you're here to see it. 

It'd be really helpful if you know how to set up a Punnett Square for this. 

I'll give you some information, in case you know what to do with it. 

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We know that Capital ( R ) is ROUND

Pretend that lowercase ( r ) is WRINKLED 

We also know that Capital ( Y ) is YELLOW 

Pretend that lowercase ( y ) is GREEN