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Mathematics 17 Online
OpenStudy (janu16):

Find the area of trapezoid help

OpenStudy (janu16):

Here

OpenStudy (alexandervonhumboldt2):

area=(base+base)/2*height

OpenStudy (anonymous):

ot u can just find the area of the rectangle and the triangle

OpenStudy (anonymous):

or*

OpenStudy (alexandervonhumboldt2):

you will need to find hegight: to find height use sin ratio

OpenStudy (janu16):

even ik the formula but there is rectangle and tiangle @AlexandervonHumboldt2

OpenStudy (alexandervonhumboldt2):

yeah

OpenStudy (alexandervonhumboldt2):

the height=sin(60)=x/8

OpenStudy (alexandervonhumboldt2):

x=6.9

OpenStudy (alexandervonhumboldt2):

height=6.9

OpenStudy (janu16):

for triangle? @AlexandervonHumboldt2

OpenStudy (alexandervonhumboldt2):

for both

OpenStudy (janu16):

so height for both is 6.9?

OpenStudy (alexandervonhumboldt2):

the puncted line is 6.9

OpenStudy (alexandervonhumboldt2):

the base for the triangle is cos60=x/8

OpenStudy (alexandervonhumboldt2):

x=4 so base =4

OpenStudy (janu16):

alright and how did you get 6.9

OpenStudy (anonymous):

Trapezoid Area= a+b / 2 (h)

OpenStudy (alexandervonhumboldt2):

area iof triangle+area of rectangle=6.9*10 + 4*6.9/2

OpenStudy (alexandervonhumboldt2):

simplify

OpenStudy (janu16):

they want the answer in radical form @AlexandervonHumboldt2

OpenStudy (mathstudent55):

You need the two bases and the height.

OpenStudy (mathstudent55):

The right side is a triangle. Notice it's a 30-60-90 triangle. You can use the ratios of the sides to find the lengths you need.

OpenStudy (mathstudent55):

Let's look at just the triangle.

OpenStudy (mathstudent55):

|dw:1425846155822:dw|

OpenStudy (mathstudent55):

We need to find x and y. |dw:1425846201878:dw|

OpenStudy (janu16):

ok help me with like how to find the height and i need the answer is radical form sso ya please help

OpenStudy (mathstudent55):

Do you remember the ratios I told you in the last problem for a 30-60-90 triangle?

OpenStudy (mathstudent55):

The hypotenuse is twice the short leg. The long leg is sqrt3 times the short leg.

OpenStudy (janu16):

square root 3 is taht what you are talking about?

OpenStudy (mathstudent55):

|dw:1425846329091:dw|

OpenStudy (mathstudent55):

Yes.

OpenStudy (janu16):

yay finally getting this ok whats next

OpenStudy (mathstudent55):

The short leg is what I called x. If the hypotenuse is twice the short leg, and the hypotenuse is 8 ft, what is x?

OpenStudy (janu16):

4?

OpenStudy (mathstudent55):

Right. Let's fill it in. |dw:1425846445786:dw|

OpenStudy (mathstudent55):

The long leg is what I called y. The long leg is sqrt3 times the short leg. How long is the long leg?

OpenStudy (janu16):

so short leg is alwys the half of hypotenuse?

OpenStudy (mathstudent55):

Yes, in a 30-60-90 triangle only.

OpenStudy (janu16):

im not sure about long lem did you say sqrt3 times 4?

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