Mathematics
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OpenStudy (janu16):
Find the area of trapezoid help
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OpenStudy (janu16):
Here
OpenStudy (alexandervonhumboldt2):
area=(base+base)/2*height
OpenStudy (anonymous):
ot u can just find the area of the rectangle and the triangle
OpenStudy (anonymous):
or*
OpenStudy (alexandervonhumboldt2):
you will need to find hegight: to find height use sin ratio
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OpenStudy (janu16):
even ik the formula but there is rectangle and tiangle @AlexandervonHumboldt2
OpenStudy (alexandervonhumboldt2):
yeah
OpenStudy (alexandervonhumboldt2):
the height=sin(60)=x/8
OpenStudy (alexandervonhumboldt2):
x=6.9
OpenStudy (alexandervonhumboldt2):
height=6.9
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OpenStudy (janu16):
for triangle? @AlexandervonHumboldt2
OpenStudy (alexandervonhumboldt2):
for both
OpenStudy (janu16):
so height for both is 6.9?
OpenStudy (alexandervonhumboldt2):
the puncted line is 6.9
OpenStudy (alexandervonhumboldt2):
the base for the triangle is cos60=x/8
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OpenStudy (alexandervonhumboldt2):
x=4 so base =4
OpenStudy (janu16):
alright and how did you get 6.9
OpenStudy (anonymous):
Trapezoid Area= a+b / 2 (h)
OpenStudy (alexandervonhumboldt2):
area iof triangle+area of rectangle=6.9*10 + 4*6.9/2
OpenStudy (alexandervonhumboldt2):
simplify
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OpenStudy (janu16):
they want the answer in radical form @AlexandervonHumboldt2
OpenStudy (mathstudent55):
You need the two bases and the height.
OpenStudy (mathstudent55):
The right side is a triangle.
Notice it's a 30-60-90 triangle.
You can use the ratios of the sides to find the lengths you need.
OpenStudy (mathstudent55):
Let's look at just the triangle.
OpenStudy (mathstudent55):
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OpenStudy (mathstudent55):
We need to find x and y.
|dw:1425846201878:dw|
OpenStudy (janu16):
ok help me with like how to find the height and i need the answer is radical form sso ya please help
OpenStudy (mathstudent55):
Do you remember the ratios I told you in the last problem for a 30-60-90 triangle?
OpenStudy (mathstudent55):
The hypotenuse is twice the short leg.
The long leg is sqrt3 times the short leg.
OpenStudy (janu16):
square root 3 is taht what you are talking about?
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OpenStudy (mathstudent55):
|dw:1425846329091:dw|
OpenStudy (mathstudent55):
Yes.
OpenStudy (janu16):
yay finally getting this ok whats next
OpenStudy (mathstudent55):
The short leg is what I called x.
If the hypotenuse is twice the short leg, and the hypotenuse is 8 ft, what is x?
OpenStudy (janu16):
4?
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OpenStudy (mathstudent55):
Right.
Let's fill it in.
|dw:1425846445786:dw|
OpenStudy (mathstudent55):
The long leg is what I called y.
The long leg is sqrt3 times the short leg.
How long is the long leg?
OpenStudy (janu16):
so short leg is alwys the half of hypotenuse?
OpenStudy (mathstudent55):
Yes, in a 30-60-90 triangle only.
OpenStudy (janu16):
im not sure about long lem did you say sqrt3 times 4?