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Mathematics 18 Online
OpenStudy (janu16):

Another trapezoid problem Find the area

OpenStudy (janu16):

Heres the pic

OpenStudy (janu16):

Ik how to find the area but im not sure how to find the hypotenuse

OpenStudy (janu16):

@mathstudent55

OpenStudy (mathstudent55):

Good. Now we get to see what the side ratios are for a 45-45-90 triangle.

OpenStudy (mathstudent55):

In a 45-45-90 triangle, you have a right triangle with two congruent angles. The sides opposite the 45-deg angles are congruent. The hypotenuse is longer than those two sides.

OpenStudy (mathstudent55):

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OpenStudy (mathstudent55):

We let the two congruent sides equal a. Now we can find h, the length of the hypotenuse using the Pythagorean theorem. \(a^2 + a^2 = h^2\) \(2a^2 = h^2\) \(h^2 = 2a^2\) \(h = \sqrt{2a^2} \) \(h = \sqrt 2 a\)

OpenStudy (mathstudent55):

Now you see that is a 45-45-90 triangle, the two legs are congruent. They have the same length. Then the hypotenuse is sqrt2 times longer than the legs.

OpenStudy (mathstudent55):

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OpenStudy (janu16):

ok now what? @mathstudent55

OpenStudy (mathstudent55):

Now you know about the 45-45-90 triangle also.

OpenStudy (mathstudent55):

Now let's deal with the trapezoid problem.

OpenStudy (janu16):

ya is the ratio sqrt 2 always for 45 90

OpenStudy (mathstudent55):

For the area of a trapezoid, we need the two bases and the height.

OpenStudy (mathstudent55):

Yes. The hypotenuse is always sqrt 2 times the legs in a 45-45-90 triangle.

OpenStudy (janu16):

alright got that part

OpenStudy (mathstudent55):

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