Another trapezoid problem Find the area
Heres the pic
Ik how to find the area but im not sure how to find the hypotenuse
@mathstudent55
Good. Now we get to see what the side ratios are for a 45-45-90 triangle.
In a 45-45-90 triangle, you have a right triangle with two congruent angles. The sides opposite the 45-deg angles are congruent. The hypotenuse is longer than those two sides.
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We let the two congruent sides equal a. Now we can find h, the length of the hypotenuse using the Pythagorean theorem. \(a^2 + a^2 = h^2\) \(2a^2 = h^2\) \(h^2 = 2a^2\) \(h = \sqrt{2a^2} \) \(h = \sqrt 2 a\)
Now you see that is a 45-45-90 triangle, the two legs are congruent. They have the same length. Then the hypotenuse is sqrt2 times longer than the legs.
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ok now what? @mathstudent55
Now you know about the 45-45-90 triangle also.
Now let's deal with the trapezoid problem.
ya is the ratio sqrt 2 always for 45 90
For the area of a trapezoid, we need the two bases and the height.
Yes. The hypotenuse is always sqrt 2 times the legs in a 45-45-90 triangle.
alright got that part
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