Question

Trig help!

Answer 1

sec(theta) = 9
find the value of
tan^2(theta)

Answer 2

@jdoe0001

Answer 3

tan^2(theta) + sec^2(theta) = 1
tan^2(theta) = 1 - sec^2(theta)
I get lost after that

Answer 4

@SithsAndGiggles

Answer 5

\(\bf 1+tan^2(\theta)=sec^2(\theta)\implies tan^2(\theta)=sec^2(\theta)-1
\\ \quad \\ \quad \\
sec(\theta)={\color{brown}{ 9}}
\\ \quad \\
tan^2(\theta)=sec^2(\theta)-1\implies [tan(\theta)]^2=[sec(\theta)]^2-1
\\ \quad \\\
[tan(\theta)]^2=[{\color{brown}{ 9}}]^2-1\)

Answer 6

thanks again bro! i really appreciate it. I think i understand this section now!

Answer 7

damn my computer is screwed up. It didnt post my latest reply where i said thanks!
youre a lifesaver. i finally understand this section now

Answer 8

yw