Question

Solve the equation.

x^2 = 150

Answer 1

Your last question is wrong by the way.

Answer 2

The other guy gave you an incorrect answer.

Answer 3

Really? what the

Answer 4

divine before telling others are wrong learn to read, 121/4 is 30.25
I told him to square root 30.25

Answer 5

Wrong.

Answer 6

4x2 = 121

(Points : 1)
30.25, −30.25
5.5, −5.5
11, −11
2.75, −2.75

Answer 7

+underline sqrt(121/4), x = 5.5, -5.5

Answer 8

See you dont just divide it.

Answer 9

you are saying the exact same thing as i said...

Answer 10

See but you have solved it wrong you just divided it.

Answer 11

divide 121 by 4
then square root your answer...

Answer 12

can you explain it instead of giving answer

Answer 13

Yeah sure.

Answer 14

Step 1 : divide both sides by 4
\[\frac{ 4x^2 }{ 4 } = \frac{ 121 }{ 4 } so x^2 = \frac{ 121 }{ 4 }\]

Answer 15

Step 2: take the square root \[x = \pm \]

Answer 16

sqrt

Answer 17

after the plusunderline aka PM

Answer 18

in front of the sqrt is \[(\frac{ 121 }{ 4 }) \]

Answer 19

which gives you x = 5.5, -5.5

Answer 20

See you find the sqrt of 30.25

Answer 21

which is 5.5

Answer 22

Which gives you 5.5, -5.5 as your final answer.

Answer 23

Now do you see how his answer is wrong @Mr1337 ?

Answer 24

Thanks can you help me out with this question ?

Answer 25

Yeah sure just re-post it below my comment here.

Answer 26

Never mind its at the top of the page.

Answer 27

There is only one step to this which is take the square root.

Answer 28

What is 150's square root?

Answer 29

12

Answer 30

12.24

Answer 31

Don't remove the decimal unless it asks. so your answer would be 12.247449, - 12.247449

Answer 32

yeah i got that

Answer 33

but your teacher would probably want it more clean so, 12.24, -12.24

Answer 34

http://gyazo.com/c03fa48920a1036d3c42442844ac200f

Answer 35

those are the answers

Answer 36

What the...

Answer 37

Let me see what i can do...

Answer 38

yeah that's why i was really confused

Answer 39

I would go with the first answer. Considering i just solve them here is how i got it -> http://www.tiger-algebra.com/drill/x2=150/

Answer 40

\[x ^{2}=150\]

square root both sides to get
\[x=\sqrt{150}\]

find a square number that goes into 150, the highest square number in my mind is 25
how many times does 25 go into 150? 6 times
you rewrite \[x=\sqrt{150}\]
to be

\[x=\sqrt{25}\sqrt{6}\]

\[\sqrt{25}=\pm5\]
which gives
\[\pm5\sqrt{6}\]

Answer 41

As i already you just confirmed the first answer i suggested :P

Answer 42

i know just thought I would help him with a simpler layout

Answer 43

Yeah that is simpler but more complex and thought out makes it easier. Since it is broken down into layers. But good job anyways.