Question

help please:

Answer 1

@Data_LG2

Answer 2

Apply pythagorean theorem: \(\sf hypotenuse^2=adjacent^2+opposite^2\) to find sides
Then apply trig ratio, to solve for the angles
\(\sf \Large{ sin \theta= \frac{opposite}{hypotenuse} -> SOH \\cos \theta=\frac{adjacent}{hypotenuse}->CAH\\tan \theta =\frac{opposite}{adjacent}->TOA}\)

Answer 3

I have no idea how to do this, I'm so confused

Answer 4

for example, let's do 4a... you are looking for angle A:

Answer 5

we'll use the the given values to solve for A:

you are given the hypotenuse and the opposite of A