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Mathematics 20 Online
OpenStudy (anonymous):

If the outliers are not included in the data set below, what is the mean of the data set? 42, 43, 46, 48, 57, 60, 96, 59, 38, 68, 29 47 48 49 52 PLEASE HELP (if you tell me how I will give you a medal)

OpenStudy (anonymous):

First, do you know what the outliers are?

OpenStudy (anonymous):

The outliers are 29 and 96?

OpenStudy (anonymous):

Right So, do you know how to find the mean?

OpenStudy (anonymous):

When I added them all up and divided by 9 I got 52, but my friend is using this confusing formula which she got that 29 is not an outlier and the answer is 48. But if 29 were not to be an outlier wouldn't the answer be 49?

OpenStudy (anonymous):

Without both numbers, the answer would be 51.2 Without 96 only, the answer would be 49

OpenStudy (anonymous):

If it were me, I would answer 49. I think it's a judgment call on your part

OpenStudy (anonymous):

Alright, thank you very much that is what i thought. So is 29 an outlier?

OpenStudy (anonymous):

I don't think that it is. I'm sorry I can't be more helpful

OpenStudy (kirbykirby):

Outliers can be tricky. Did they give you a specific formula to use to determine outliers? Or you just "eyeball" the data set?

OpenStudy (anonymous):

Well my friend asked me for help and I am not as advanced as her. She gave me the formula but I do not understand it.

OpenStudy (anonymous):

Lower limit: Q1-1.5*IQR Upper Limit: Q3 +1.5*IQR

OpenStudy (kirbykirby):

Ah ok so whatever is above the upper limit, or below the lowe limit will be considered an outlier. First, Q1 is the lower quartile. Do you know how to find this?

OpenStudy (kirbykirby):

or the first quartile

OpenStudy (anonymous):

Nevermind, thank you for your help I got the answer = 49. Thank you so so much for helping me!!

OpenStudy (kirbykirby):

Ah all right then, hehe.

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