Mathematics
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OpenStudy (anonymous):
please help me......
If 6/11 of k is 8/41, what is 3/11 of k?
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OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
lol i meant
\[\frac{3}{11}\]is half of
\[\frac{6}{11}\] right?
OpenStudy (anonymous):
yes
OpenStudy (misty1212):
so what is half of \[\frac{8}{41}\]?
OpenStudy (anonymous):
but isn't that a whole different problem? i dont understand why we have to multiply that by 1/2
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OpenStudy (misty1212):
?
OpenStudy (anonymous):
(6/11)k = (8/41)
solve for just k
and find (3/11) of k
OpenStudy (anonymous):
u multiply 1/2 times 8/41 right?
OpenStudy (misty1212):
yes that is one way to say it
OpenStudy (misty1212):
i would say "take half of it" because it is pretty clear that half of eight is four
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OpenStudy (anonymous):
but why ?
OpenStudy (anonymous):
y do you take half of 8/41?
OpenStudy (misty1212):
no need to solve for \(k\)
just take half of \(\frac{8}{41}\)
OpenStudy (misty1212):
ok lets to another simpler one
OpenStudy (misty1212):
if
\[10\times x=50\] what is
\[5\times x\]?
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OpenStudy (anonymous):
5?
OpenStudy (misty1212):
no
OpenStudy (misty1212):
if \[10x=50\] then \[x=5\] but if
\[10x=50\] then
\[5x=25\]
OpenStudy (misty1212):
that is because no matter what \(x\) is, \(5x\) is half of \(10x\)
OpenStudy (anonymous):
o okay
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OpenStudy (misty1212):
since \(\frac{3}{11}\) is half of \(\frac{6}{11}\) that means
\[\frac{3}{11}k\] is half of
\[\frac{6}{11}k\]
OpenStudy (misty1212):
you are told that
\[\frac{6}{11}k=\frac{8}{41}\] that makes
\[\frac{3}{11}k=\frac{4}{41}\] half of it
OpenStudy (anonymous):
hmmmm..... i think i see now....