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Find the second solution of a differential equation: given that y_1=e^x is a solution of y"-y=0 on the internval (-inf,inf) use reduction of order to find a second solution... I got to here: y'=ue^x+ (e^x)u' and y"=ue^x+2(e^x)u' + (e^x)u" Then plugged it back in so: e^x(u''+2u')= 0. I know I need to make a substitution but I don't get what happens from here, any help?
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