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Algebra II question. Will Medal!
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what's your question?
It's in the attachment. I would like to know how to solve for this
okay, you want to rearrange the equation to make y the subject in the form y=mx+c attempt this, post your attempt and I will correct you if needed
@BloomLocke367
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also know that the y intercept is the constant
5=-10-1/2y
*5=-10-1/2y
\[-10x-\frac{ 1 }{ 2 }y=5\] \[2(-10x)-(2)(\frac{ 1 }{ 2 }y)=2(5)\]
multiply out, then rearrange for y=mx+c
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the constant C is your y intercept
where did the 2 come from?
Was it reciprocal?
-2x-1y=10
@amorfide
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you had a fraction, so you multiply by 2 because you want y not half of y
-20x-y=10 rearrange to get y=mx+c what do you get
y=-20x-10
okay so c=-10 therefore the y intercept is -10
Thanks!
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