Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (inexilewetrust):

Algebra II question. Will Medal!

OpenStudy (inexilewetrust):

OpenStudy (bloomlocke367):

what's your question?

OpenStudy (inexilewetrust):

It's in the attachment. I would like to know how to solve for this

OpenStudy (amorfide):

okay, you want to rearrange the equation to make y the subject in the form y=mx+c attempt this, post your attempt and I will correct you if needed

OpenStudy (inexilewetrust):

@BloomLocke367

OpenStudy (amorfide):

also know that the y intercept is the constant

OpenStudy (inexilewetrust):

5=-10-1/2y

OpenStudy (inexilewetrust):

*5=-10-1/2y

OpenStudy (amorfide):

\[-10x-\frac{ 1 }{ 2 }y=5\] \[2(-10x)-(2)(\frac{ 1 }{ 2 }y)=2(5)\]

OpenStudy (amorfide):

multiply out, then rearrange for y=mx+c

OpenStudy (amorfide):

the constant C is your y intercept

OpenStudy (inexilewetrust):

where did the 2 come from?

OpenStudy (inexilewetrust):

Was it reciprocal?

OpenStudy (inexilewetrust):

-2x-1y=10

OpenStudy (inexilewetrust):

@amorfide

OpenStudy (amorfide):

you had a fraction, so you multiply by 2 because you want y not half of y

OpenStudy (amorfide):

-20x-y=10 rearrange to get y=mx+c what do you get

OpenStudy (inexilewetrust):

y=-20x-10

OpenStudy (amorfide):

okay so c=-10 therefore the y intercept is -10

OpenStudy (inexilewetrust):

Thanks!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!