PLEASE HELP GIVING MEDAL
Which is the quadratic variation equation for the relationship?
y varies directly with x2 and y = 72 when x = 6.
A.
y = 4x^2
B.
y = 2x^2
C.
y = x^2 + 25
D.
y = 12x
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OpenStudy (anonymous):
@dire
OpenStudy (anonymous):
@Directrix
Nnesha (nnesha):
do you know the formula for direct variation ??
OpenStudy (anonymous):
cananyone help please?
OpenStudy (anonymous):
not really
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OpenStudy (anonymous):
sorry
OpenStudy (ilovecake):
y varies directly with x2"
means y = k x^2 (where k is the number you want to find)
they gave you x and y, plug in
so 72 = k (6^2) and solve for k
Nnesha (nnesha):
\[\huge\rm y =kx \]formula for direct variation
but u need equation for quadratic variation so x suppose to be square \[\huge\rm y = kx^2\] now just substitute x and y values
OpenStudy (anonymous):
72x6?
Nnesha (nnesha):
nope first take square of 6
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