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Mathematics 13 Online
OpenStudy (anonymous):

PLEASE HELP GIVING MEDAL Which is the quadratic variation equation for the relationship? y varies directly with x2 and y = 72 when x = 6. A. y = 4x^2 B. y = 2x^2 C. y = x^2 + 25 D. y = 12x

OpenStudy (anonymous):

@dire

OpenStudy (anonymous):

@Directrix

Nnesha (nnesha):

do you know the formula for direct variation ??

OpenStudy (anonymous):

cananyone help please?

OpenStudy (anonymous):

not really

OpenStudy (anonymous):

sorry

OpenStudy (ilovecake):

y varies directly with x2" means y = k x^2 (where k is the number you want to find) they gave you x and y, plug in so 72 = k (6^2) and solve for k

Nnesha (nnesha):

\[\huge\rm y =kx \]formula for direct variation but u need equation for quadratic variation so x suppose to be square \[\huge\rm y = kx^2\] now just substitute x and y values

OpenStudy (anonymous):

72x6?

Nnesha (nnesha):

nope first take square of 6

OpenStudy (anonymous):

36?

OpenStudy (ilovecake):

look at link http://openstudy.com/study#/updates/53054dade4b022471a64d160

Nnesha (nnesha):

yep so now you have \[\huge\rm 72 = 36k\] solve for k there is 36 times k so you have to do opposite of multiply to cancel out 36 from right side

OpenStudy (anonymous):

0?

OpenStudy (anonymous):

@Nnesha

OpenStudy (ilovecake):

Does the link help? @ACU17

OpenStudy (anonymous):

not really

Nnesha (nnesha):

nope divide both side by 36

Nnesha (nnesha):

yep right side 36/36 cancel out what about other side you need to divide "both side" by 36

OpenStudy (ilovecake):

are you kidding?? that is clear as day

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