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Mathematics 7 Online
OpenStudy (anonymous):

Hey, I need help with probability please :)

OpenStudy (jokersmart):

This MIGHT help: http://www.mathgoodies.com/lessons/vol6/intro_probability.html

OpenStudy (anonymous):

Marco created a table to help him represent the sample space of spinning a spinner and flipping a coin. Result of coin toss Red Green Yellow Heads Red, heads Green, heads Yellow, heads Tails Red, tails Green, tails Yellow, tails What is the probability that the result of the spin is green and the coin lands tails up? one over six two over six three over six four over six

OpenStudy (anonymous):

@jokersmart

Directrix (directrix):

How many times do you count "Green, Tails" in the chart?

OpenStudy (anonymous):

@Data_LG2 @Directrix @bibby @inowalst @Nnesha @paki @pooja195

OpenStudy (anonymous):

Oops sorry lol

OpenStudy (anonymous):

once

Directrix (directrix):

How many times do you count "Green, Tails" in the chart? @77777jeannie77777

OpenStudy (anonymous):

Oh so that's the answer thx:) lol can u help with some more?? I'll open another question

OpenStudy (anonymous):

1/3

OpenStudy (anonymous):

once

OpenStudy (anonymous):

1 out of 3

OpenStudy (anonymous):

1

Directrix (directrix):

We are not finished, yet. Hold on. Okay, that is the numerator of the probability fraction. Next question: How many entries are in the chart?

Directrix (directrix):

@77777jeannie77777 How many entries are in the chart?

OpenStudy (anonymous):

wait, a or b?

OpenStudy (anonymous):

in total?

OpenStudy (anonymous):

6

OpenStudy (anonymous):

i think

Directrix (directrix):

Red, heads Green, heads Yellow, heads Red, tails Green,tails Yellow, tails These ^^^^^ are the entries in the chart. There are more than one. Count them. The number of possible outcomes will be the denominator of the probability fraction.

OpenStudy (anonymous):

right??

Directrix (directrix):

Yes, 6.

Directrix (directrix):

So, the probability of (green, tails) = 1/6.

OpenStudy (anonymous):

Lol I think the answer is A: 1/6

OpenStudy (anonymous):

am i right or wrong? just tell me that

OpenStudy (anonymous):

ok thanks :):):)

OpenStudy (anonymous):

ill open another question

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