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MIT 18.01 Single Variable Calculus (OCW)
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why in lecture 1, the area of triangle was only '2' instead of 2XoYo, although from calculation, the second value came out.
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A characteristic of this function (y = 1/x) is that for any non-zero value of x, x*y = 1. Therefore, the area of any triangle enclosed by axes and tangent to the function y = 1/x is necessarily 2. Specifically (see video at 40:30): \[Area = 1/2(2x _{0})(2y _{0})=2\] because \[x _{0}*y _{0} = 1.\]
Area = 1/2 * base* height Plugging in the value using the x-intercept for base and y-intercept for height, we get Area = 1/2* 2xo *2yo = 2xo*yo We know that the function y = 1/x Therefore, at the point (xo,yo) or (xo,1/xo), the value of yo = 1/xo Plugging in the value, we always get the area equals to 2.
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