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Mathematics 8 Online
OpenStudy (anonymous):

help me please

OpenStudy (anonymous):

Don't show your breasts on Os..

OpenStudy (anonymous):

\[\frac{ 6 }{ 5 } \times \left(-\begin{matrix}1 \\ 6\end{matrix}\right)\]

OpenStudy (anonymous):

one sec

OpenStudy (ahsome):

@NadiaElhaj_1, is that a matrix on the right, or a fraction?

OpenStudy (anonymous):

its suppose to be - 1over6

OpenStudy (ahsome):

Ahh, I see Your question: \[\frac{6}{5}\times\frac{1}{6}\] Simply multiply the numerators and the denominators together: \[\frac{6}{5}\times\frac{1}{6}\]\[\frac{6\times1}{5\times6}\]\[\frac{6}{30}\]Now, simply as much as possible.\[\frac{6}{30}\]\[\frac{1}{5}\]And thats it :)

OpenStudy (anonymous):

6/5x1/6 (1x6)/(5/6) 6/30 1/5

OpenStudy (anonymous):

omg thank you guys so much thanks for not only giving the answer but showing how to do it that help a lot i wanna give u both medals so can everyone medal @HELPMEPLZ!! and @Ahsome

OpenStudy (igreen):

@Ahsome We have to guide them..there needs to be participation..plus it was -1/6..

OpenStudy (ahsome):

@iGreen, from my side I don't see a negative sign. Sorry :(

OpenStudy (ahsome):

No problem @NadiaElhaj_1

OpenStudy (anonymous):

i don't see a negative sign either

OpenStudy (igreen):

\(\dfrac{6}{5} \times -\dfrac{1}{6}\) Just multiply the numerators together and the denominators together: \(\dfrac{6 \times -1}{5 \times 6}\)

OpenStudy (anonymous):

-6 / 30 this is what i got

OpenStudy (ahsome):

Thats it @NadiaElhaj_1 :) I just don't see a negative sign, thats all :)

OpenStudy (anonymous):

simplified is -1/5

OpenStudy (igreen):

Yes, now simplify it..divide the numerator and denominator by 6. -6 / 6 = ? 30 / 6 = ?

OpenStudy (igreen):

@Ahsome @HELPMEPLZ!!

OpenStudy (ahsome):

@iGreen, where did you get 6 from

OpenStudy (igreen):

It's a common multiple between -6 and 30.

OpenStudy (ahsome):

Good :)

OpenStudy (anonymous):

please everyone give each other medals cuz u guys are awesome :D

OpenStudy (igreen):

Just remember guys, GUIDE the asker to the answer, we need his/her participation :)

OpenStudy (anonymous):

Non for me huh?

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