Question

Show that (tan 30 + x) = 2 tan (60- x) can be written in tan^2 x + (6sqrt3) tan x -5= 0.

Answer 1

What I did was,
(tan 30 + tan x)/1 + tan30tanx = 2 (tan60-tanx)/1-tan60tanx
sqrt3/3 + tan x / 1+sqrt3/3 tanx = 2sqrt3 - 2tanx

Answer 2

Is it right so far?

Answer 3

Do you mean:
\[ (tan 30 + x) = 2 tan (60- x)\]Is the same as:\[ tan^2 (x) + \sqrt[6]{3}\times tan (x) -5= 0. \]

Answer 4

It's okay. I know where I went wrong alrd.

Answer 5

Ok then. If you still need help, just say so