Solve the following system of equations: x - 2y = 6 2x - 4y = 10
See, make either coefficient of \(x\) or \(y\) just equal to what is that in second equation..
Firstly, multiply first equation by \(2\)..
"If you multiply equation one by 2 you get 2x-4y=12 2x-4y=10" Since 2x-4y=2x-4y, that implies that 12=10, which is false, so there is no solution. The lines are parallel.
there is a solution
So, you will get two equations as : \[2x - 4y = 12 \\ 2x - 4y = 10\]
Method two: x-2y=6 --> y=x/2-3 2x-4y=10 --> y=x/2-5/2 Both lines have the same slope but a different intercept, ergo, parallel, and no solution.
yes^
As, at the same time, \((2x-4y)\) cannot be equal to \(10\) and \(12\) both, so this means lines are parallel and it is having NO SOLUTION..
@blake57roger is right
Thanks
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