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Mathematics 22 Online
OpenStudy (freemap):

In the triangle below, calculate the value of x.

OpenStudy (freemap):

OpenStudy (anonymous):

Sin θ = o/h

OpenStudy (freemap):

Is 4.75 the correct answer

OpenStudy (caominhim):

no

OpenStudy (caominhim):

multiply 12*sin(57)

OpenStudy (freemap):

These are the answer choices. a. 10 b.5 c.11.85 d.4.75

OpenStudy (caominhim):

sin(theta) = opposite/hypotenuse therefore hypotenuse*sin(theta) = opposite

OpenStudy (freemap):

I'm sorry but I don't quite understand. I did sin 57. It gave me .8386

OpenStudy (freemap):

please help, I don't understand

OpenStudy (anonymous):

Sin θ = a/h sin(57) = x/12 0.436 = x/12 0.436(12) = x 5.23 = x

OpenStudy (anonymous):

The answer would be 5 if I only used one decimal place.

OpenStudy (freemap):

Thanks, Could you explain why you got 12 from?

OpenStudy (freemap):

where

OpenStudy (freemap):

I did sin57 and it gave me 8386

OpenStudy (anonymous):

H = 12 h is the hypotenuse

OpenStudy (freemap):

I'm just trying to understand not challenge, I have more to do. I just want to know how to do them. Where did you get 0.436? I did sin 12, and the √ and did not get 0.436. Thanks so much

OpenStudy (freemap):

I didn't type the quesion marks have no clue where that came from

OpenStudy (freemap):

I the place of the question marks I said I also tried the squre root and didn't get the .436

OpenStudy (caominhim):

hold up, no it's not 5

OpenStudy (caominhim):

make sure your calc is in degree mode

OpenStudy (freemap):

Its in dregree mode. I press sin and put 57 and enter is that how you do it?

OpenStudy (anonymous):

@caominhim you're right.

OpenStudy (anonymous):

The answer would be 10

OpenStudy (freemap):

So the answer isn't 5?

OpenStudy (caominhim):

multiply the hypotenuse by sin(57)

OpenStudy (anonymous):

No it's 10.

OpenStudy (caominhim):

because sin(theta) = opposite/hypotenuse

OpenStudy (anonymous):

I had to put it in degrees.

OpenStudy (freemap):

Its in dregree mode. I press sin and put 57 and enter is that how you do it?

OpenStudy (caominhim):

SOHCAHTOA sin = opposite/hypotenuse cos = adjacent/hypotenuse tan = opposite/ adjacent

OpenStudy (anonymous):

@freemap yes. that is right.

OpenStudy (caominhim):

and yes that gives you the sin value, now multiply that by 12

OpenStudy (freemap):

When I do that Why do I keep getting .8386

OpenStudy (caominhim):

because sin(57) = .8386705679

OpenStudy (freemap):

Thanks I just didn't understand where .436 came from. sorry for being annoying.

OpenStudy (caominhim):

it's cool, though i don't know where you got .436 from

OpenStudy (freemap):

Thats what lia.may got

OpenStudy (caominhim):

oh that's the radian value of sin(57)

OpenStudy (freemap):

oh okay thanks so much for working with me

OpenStudy (caominhim):

no problem

OpenStudy (freemap):

Who get the medal?

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