Question

How would I find the derivative sin^-1(x^2)? Please I've been at this for a long time

Answer 1

It's the derivative of \[\sin ^{-1}(x^2)\] I know \[\sin y= x ^{2}\]

Answer 2

yes, then differentiate on both sides

Answer 3

y' cos(y) = 2x

Answer 4

then
cos(y)= sqrt( 1- sin^2(y) )

Answer 5

y ( sqrt (1 - x^4 ) ) = 2x

Answer 6

I meant
y' ( sqrt (1 - x^4 ) ) = 2x

Answer 7

y' = 2x/ ( sqrt (1 - x^4 ) )

Answer 8

oaky thank you!