Question

solve this radical equation and determine if the solution is extraneous

Answer 1

\[\sqrt{2x - 3} + 6 = 1\]

Answer 2

@Nnesha @TrojanPoem

Answer 3

Take 6 to other side..

Answer 4

square both sides then

Answer 5

so subtract 6 ?

Answer 6

yep..

Answer 7

i get sqrt(2x - 3) = 1

Answer 8

1-6 = ??

Answer 9

-5

Answer 10

and then

Answer 11

Square it..

Answer 12

how

Answer 13

take squares both the sides, simple..!! :P

Answer 14

\[\sqrt(2x-3)=-5\]
\[2x-3=25\]
\[2x=28\]
\[x=14\]

Answer 15

2x - 3^2 = -5^2

Answer 16

\[(\sqrt{2x-3})^2 = (-5)^2\]

Answer 17

when you plug it back in to check , make sure to take the negative root tho

Answer 18

OHH ok

Answer 19

tyty