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Algebra 23 Online
OpenStudy (anonymous):

Help me on this algebra question? :) Perpendicular lines Select the equation of a line that is perpendicular to the line on the graph and passes through the point (-1, 2). A. y= 2x + 4 B. y= -2x + 2 C. y= -1/2x + 2 D. y= 2x - 1 I'll attach the graph

OpenStudy (anonymous):

pooja195 (pooja195):

do you know what the equation of the line is?

pooja195 (pooja195):

also welcome to openstudy!

OpenStudy (anonymous):

I do not & thank you :)

pooja195 (pooja195):

ok what number is the line on on the Y axis?

pooja195 (pooja195):

the vertical line is the Y axis

OpenStudy (anonymous):

The line's on -1 for the y-axis?

pooja195 (pooja195):

yep and so we have y=mx-1 now what is the line on on the X axis?

OpenStudy (anonymous):

-2

OpenStudy (anonymous):

Is it that one equation, y-y1 = m(x-x1) ?

pooja195 (pooja195):

wait we've done something wrong the slope is rise/run so -1 is right do u know how to find the slop?

pooja195 (pooja195):

slope

pooja195 (pooja195):

line increasing so that mean positive slope line decreasing then you should have negative slope

OpenStudy (anonymous):

i don't think I remember too much. I havent done this since last year

pooja195 (pooja195):

http://prntscr.com/6g50p5

OpenStudy (anonymous):

rise is 1, would the run be 2 or -2? that confuses me a little bit since it's going to the left lol

pooja195 (pooja195):

left = neg so -2 i need to go @Nnesha please finish :*

Nnesha (nnesha):

\(\color{blue}{\text{Originally Posted by}}\) @spanish356547 rise is 1, would the run be 2 or -2? that confuses me a little bit since it's going to the left lol \(\color{blue}{\text{End of Quote}}\) yes right rise is one and run is 2 so rise /run line is decreasing right so that's why slope should be negative -rise/run so slope is ?

Nnesha (nnesha):

okay so perpendicular slope should be negative reciprocals so you need to change sign of graph slope and flip it upside down and then find b like we did bofre on a previous post :)

Nnesha (nnesha):

before*

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