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A triangle has coordinates A (1, 5), B (-2, 1) and C (0, -4). What are the new coordinates if the triangle is dilated with a scale factor of 1/5?
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@ganeshie8 my last question
@hartnn
rule for dilation with a scalefactor of \(k\) : \[(x,~y) \longrightarrow (kx~,ky)\]
simply multiply 1/5 to all the coordinates
\[(1,5) \longrightarrow(\color{blue}{\frac{1}{5}}*1,~\color{blue}{\frac{1}{5}}*5)~~ =~~ (\frac{1}{5},~1)\]
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see if you can work out remaining two vertices
1/5 --> (1/5*-2, 1/5 *1) = (-2/5, 1)
oops i meant (-2,1)
try again
ohh ok
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ok so this is all i got
1/5 --> (1/5*1, 1/5*5) = (1/5,1)
(-2,1) --> (1/5*-2,1/5*1) = (-2/5,1/5)
(0,-4) --> (1/5*0,1/5*-4) = (0,-4/5)
Perfect!
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ok am i done here?
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