[4.10] Find the value of y. A 45, 45, 90 degree right triangle is drawn. One of the 45 degree angles is labeled. The leg adjacent to that 45 degree angle i (4 points) 5 5 times the square root of 2. 10 5 times the square root of 3.
use the facts that \[\sin(\theta)=\frac{opposite}{hypotenuse}\] \[\cos(\theta)=\frac{adjacent}{hypotenuse}\]
which one is it?
y is the hypotenuse (longest side in a right angle triangle), and we got the adjacent side, so you can use cos
\[\cos(45)=\frac{5}{y}\]
adjacent is next to and opposite is...well opposite right?
then you know from you r trig circle that 45=pi/4 and cos(45)=sin(45)=root(2)/2 now y=5/(root2/2)=10/root(2) or 5root(2)
yep
but to respect to the angle you know (45 in this case)
so im guessing i set it up like this?\[\frac{ 45 }{ 1 }X \frac{ 5 }{ y }\]
you need the cosine
ur not making sence to me, can you please just tell me the answer?
plz
dude!
i have been warned multiple times that i cant give out answers like that. you need to solve it by yourself, i can just help you understand
it could be clearer to represent cos(45) = root(2)/2 right away
i have no idea what you are trying to explain though! its all like mumbo jumbo!
\[\frac{\sqrt{2}}{2} = \frac{5}{y}\]
now you can solve it
wat bout the sqr root? i dont know how to solve that!
do you know how to solve equations? the root(2) is a constant
so i do 10=sqwrroot 2y?
yep
which is 5?
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