Question

Graph the circle with the center at (3,-2) which also passes through the point (0,2). Find the radius.

Answer 1

well the form of the circle you need is

\[(x - h)^2 + (y - k)^2 = r^2\]

(h, k) is the centre of the circle

so your circle is

\[(x - 3)^2 + (y + 2)^2 = r^2\]

now substitute the point x = 0 and y = 2 to find r^2

then take the square root to find the radius

Answer 2

thank you