Question

Which of the following is not an equivalent form of the compound inequality

x + 15 less than or greater to 12 and x + 15 greater than or equal to 5

Answer 1

a. 12 greater than or equal to x + 15 greater than or equal to 5
b. -3 greater than or equal to x greater than or equal to -10
c. A number line with a closed circle on -10, a closed circle on -3, and shading in between.
d. A number line with a closed circle on -10, shading to the left, and a closed circle on -3, shading to the right.

Answer 2

I was thinking b

Answer 3

@Nnesha

Answer 4

For the first part did you mean less than or equal to? I dont understand the `less than or greater to`

Answer 5

Yes I did

Answer 6

@Nnesha

Answer 7

Well ok, then \[x+15 \le 12 \implies x \le ~?\]\[5 \le x+15 \implies x \le ~?\]

Answer 8

x<=-3

Answer 9

solve for both.

Answer 10

x>=-10

Answer 11

I was just working on the second one

Answer 12

Alright, so you have \[1.~ x\le -3 ~,~ 2. -10\le x\] We can combine 1. and 2. to form one compound inequality as so: \[-10 \le x \le-3\]

Answer 13

One sec, I will brb.

Answer 14

Ok thanks

Answer 15

U still there?

Answer 16

Answer is D right?

Answer 17

I am lost now.........

Answer 18

Yes it is.

Answer 19

Can you explain to me why you think it is D?

Answer 20

I think it was d because it was the only one that didn't match up when I graphed it
However I wasn't sure that I was graphing it correctly