Question

How to show : if gcd (a1,a2,a3) =1 and gcd(b1,b2,b3) =1, then gcd(a1b1,a2b2,a3b3)=1?
Please, help

Answer 1

@ikram002p

Answer 2

counter example :

(3, 4, 4) = 1
(4, 3, 3) = 1

however (3*4, 4*3, 4*3) = 12

Answer 3

Is there more information, since I don't think this is actually true.

Answer 4

Yeah... well beat me to it haha.

Answer 5

Ok, the problem is if f(x) , g(x) are primitive, show that f(x)*g(x) is primitive also

Answer 6

and primitive mean: gcd(coefficients )=1

Answer 7

I got it, :) thanks anyway