find the value of x.
a. 4
b. 8 square root of 2 / 2
c. 4 square root of 2
d. 8 square root of 2
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OpenStudy (anonymous):
OpenStudy (anonymous):
plz help
OpenStudy (anonymous):
Do you know how to do pythagorean theorum?
OpenStudy (anonymous):
somewhat
OpenStudy (anonymous):
a^2 + b^2 = c^2
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OpenStudy (amorfide):
you are give two angles and one side length so you can use the sin rule
\[\frac{ a }{ sinA }=\frac{ b }{ sinB }\]
where lower case letters are side lengths
and capital letters are angles opposite the side length
OpenStudy (amorfide):
oh yeah pythagoras
OpenStudy (anonymous):
The 2 left and right sides of the triangle are equal, they are the shorter sides
OpenStudy (anonymous):
because they're both 8, you will do 8^2 + 8^2
OpenStudy (anonymous):
then find the square root of that
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OpenStudy (anonymous):
64 + 64
?
OpenStudy (anonymous):
then find the square root of that
OpenStudy (anonymous):
128
OpenStudy (anonymous):
Usually teachers would prefer that you round to the nearest tenth decimal
OpenStudy (anonymous):
so what do i do next?
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OpenStudy (anonymous):
find the square root of 128
OpenStudy (anonymous):
11. something
OpenStudy (anonymous):
11.3
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
teachers usually prefer rounding to the nearest tenth decimal place
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OpenStudy (anonymous):
whats next?
OpenStudy (anonymous):
thats the answer to x
OpenStudy (anonymous):
but thats not an option
OpenStudy (anonymous):
it isn't?
OpenStudy (anonymous):
no
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OpenStudy (amorfide):
11.3=8root2
OpenStudy (anonymous):
oh ok d then ty!
OpenStudy (amorfide):
credit goes to alvatraz
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
I haven't learned roots yet so I didn't know
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OpenStudy (anonymous):
ty for the medal
OpenStudy (anonymous):
sure
OpenStudy (anonymous):
can someone check if its really d?? plzz
OpenStudy (anonymous):
can u plzz check the answer?? @pitamar
OpenStudy (anonymous):
Yes seems fine
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