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Mathematics 22 Online
OpenStudy (anonymous):

find the value of x. a. 4 b. 8 square root of 2 / 2 c. 4 square root of 2 d. 8 square root of 2

OpenStudy (anonymous):

OpenStudy (anonymous):

plz help

OpenStudy (anonymous):

Do you know how to do pythagorean theorum?

OpenStudy (anonymous):

somewhat

OpenStudy (anonymous):

a^2 + b^2 = c^2

OpenStudy (amorfide):

you are give two angles and one side length so you can use the sin rule \[\frac{ a }{ sinA }=\frac{ b }{ sinB }\] where lower case letters are side lengths and capital letters are angles opposite the side length

OpenStudy (amorfide):

oh yeah pythagoras

OpenStudy (anonymous):

The 2 left and right sides of the triangle are equal, they are the shorter sides

OpenStudy (anonymous):

because they're both 8, you will do 8^2 + 8^2

OpenStudy (anonymous):

then find the square root of that

OpenStudy (anonymous):

64 + 64 ?

OpenStudy (anonymous):

then find the square root of that

OpenStudy (anonymous):

128

OpenStudy (anonymous):

Usually teachers would prefer that you round to the nearest tenth decimal

OpenStudy (anonymous):

so what do i do next?

OpenStudy (anonymous):

find the square root of 128

OpenStudy (anonymous):

11. something

OpenStudy (anonymous):

11.3

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

teachers usually prefer rounding to the nearest tenth decimal place

OpenStudy (anonymous):

whats next?

OpenStudy (anonymous):

thats the answer to x

OpenStudy (anonymous):

but thats not an option

OpenStudy (anonymous):

it isn't?

OpenStudy (anonymous):

no

OpenStudy (amorfide):

11.3=8root2

OpenStudy (anonymous):

oh ok d then ty!

OpenStudy (amorfide):

credit goes to alvatraz

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

I haven't learned roots yet so I didn't know

OpenStudy (anonymous):

ty for the medal

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

can someone check if its really d?? plzz

OpenStudy (anonymous):

can u plzz check the answer?? @pitamar

OpenStudy (anonymous):

Yes seems fine

OpenStudy (anonymous):

oh ok thx

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