Solve the system of equations 4x + 3y = 13 y=- x + 4
ok which method would you like to use?
I totally get these backwards, could you help figure this out
\[4x+3(-x+4)=13\] the x has a negative right and lets use substitution here its easier
all you do if take y=- x + 4 and plug it in place of the 1st equation
now solve from there
do I add or subtract from the 13
no first distribut 3 so 3 x -x = ? 3 x4 =?
7 x - 13
no....we are MULTIPLYING 3 x -x = ? 3 x4 =?
ok then 12 x
the x was for multiplication not 12x just 12 whats 3 times -x ?
\[4x+3(-x+4)=13\] distribute \[4x-3x+12=13\] combine like terms \[1x=1\] divide x=1
-12 right divided by 12 = 1
I already did that part for you now we have to substitute for X on the 2nd equation \[y=-(1)+4\] substitute 1 in place of X \[y=-1+4\] \[y=3\]
so your final answer is?
(3, 4) would this be the answer?
where did u get 4 from?
i already did all the work now u make the coordinates i tell u what equals what x= ? y= ?
(3,12)
Look back at my work
if x=1 y=3 what is your coordinate?
-3,-16 ? I am confused
I gave u the values there right there \[X=1~~~Y=3\]
Now make the coordinates
ok, now I see it would be (1,3)
\(\huge\color{RED}{CONGRATS!!!!!}\)
Thanks so much, now i am going to try to figure this out online. I will let you know how I did in a bit.
your welcome =)
I have to go somewhere soon, so thanks again pooja
hahah your welcome :) also welcome to openstudy! :D
thanks, there is so much more to learn, I forgot how to do all of these problems :)
hehe tag me anytime :)
@wopwop if anythings you now know that pooja is always ready for action and the rest of us owls :) welcome :D
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