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find the exact value of sin(cos inverse(-3/7)+ tan inverse (9/4))
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\[\sin(\cos^{-1} (-3/7)+ \tan^{-1} (9/4))\]
arccosine and arctan given you the angle given that the result are those numbers
sin(30 degrees) = 1/2 arcsin(1/2) = 30 degrees
The first thing to do would be to find the angles from the arc-trig functions
Can you do those?
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You could also draw two triangles
|dw:1426489613973:dw| (-3/7) is cos of angle a, (9/4) is the tangent of angle b
sin(a+b) = sin(a)+cos(b)+cos(a)+sin(b)
|dw:1426489861319:dw| fixed, the 7 should have been positve
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