Question

Find the zeros of: y = 2x^3 + 2x^2 - 40x.

Answer 1

set the value of y to 0 and then solve.
0 = 2x^3 + 2x^2 - 40x
factor out the x
0 = x(2x^2 + 2x - 40)
then the 2 to make it easier
0 = 2x(x^2+x-20)

0 = 2x(x-4)(x+5)

so x = 0, -5, 4 <- answer

Answer 2

@BGrg007 - thank you so much!

Answer 3

np