What is the solution to the system? Line 1 x y –2 –4 –1 –1 Line 2 x y 2 3 3 1 ( , )
why not graph them both? both are LINEar equations, and thus their graph is a LINE to graph a line, all you need is two points and you have two for each plot them both, where they meet, or "intersect", that's the solution to the system
I need help finding the y-intercept
@jdoe0001
well... you really don't need it, just to graph them though
You need the y-intercept to graph, right?
nope to graph a line, all you need is two points |dw:1426550197782:dw|
So, all I need is the slope?
well... you don't.... why not use the points given, and plot both functions?
you could get the equations, sure and make them slope-intercept form, if you wish and use that will yield the same though
Is it (1,5)?
Do you still need help on this?
If you put this both to a linear equation (I got from point slope formula) you get y=3x+2 and y=-2x+7 set these two together 3x+2=-2x+7 x=1 plug that back in to any of the linear equations, and you get 5. so yeah, your right, it's (1,5)
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