Mathematics
12 Online
OpenStudy (anonymous):
Help FOIL!
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OpenStudy (anonymous):
(2x+3) (4x - 2)
OpenStudy (anonymous):
i got 12x +12-6
OpenStudy (anonymous):
multiply the first term in each parenthesis. then the outer terms together. then the inner then the last
OpenStudy (anonymous):
No thats not right
OpenStudy (anonymous):
I did
2x* 4x= 8x
2x*2=4x
3*4=12
3*2=6
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OpenStudy (anonymous):
then you combine like terms
8x + 4x= 12x
OpenStudy (anonymous):
the first numbers you multiplied both have a x. that mean that it will be x^2. so it is actually 8x^2
OpenStudy (anonymous):
Ohh ok
OpenStudy (anonymous):
so that changes everything. Then you have to remember that the 4 and the 3 both have a x too.
OpenStudy (anonymous):
\[2x \times4x=8x ^{2}\]
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OpenStudy (anonymous):
\[2x \times-2=-4x\]
OpenStudy (anonymous):
So you have 8x^2 4x 12x 6
correct?
OpenStudy (anonymous):
then combine (add) 4x and 12x?
OpenStudy (anonymous):
\[3x*4x=12x^2 and 3x*-2=-6x\]
OpenStudy (anonymous):
So the final answer is 8x^2+ 16x -6
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OpenStudy (anonymous):
yeah thats right :)
OpenStudy (anonymous):
:D
OpenStudy (anonymous):
*high five* haha
OpenStudy (anonymous):
That isnt an answer :(
OpenStudy (anonymous):
8x2+ 8x – 6
6x2 + 13x – 6
6x2 – 5x – 6
6x2 – 13x – 6
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OpenStudy (anonymous):
oh we forgot that there are three numbers with x sorry. when we multiply 4x*3x it will be 12x^2 not 12x
OpenStudy (anonymous):
8x^2+ 8x -6
6x^2+ 13x-6
6x^2-5x-6
6x^2-13x-6
OpenStudy (anonymous):
So A? its the only one that is 8x^2
OpenStudy (anonymous):
wait there arent three numbers with x sorry i was confused. yeah its A
OpenStudy (anonymous):
Im not guessing I know its A. I just read the problem wrong. sorry for all of the confusion!