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Mathematics 12 Online
OpenStudy (anonymous):

Help FOIL!

OpenStudy (anonymous):

(2x+3) (4x - 2)

OpenStudy (anonymous):

i got 12x +12-6

OpenStudy (anonymous):

multiply the first term in each parenthesis. then the outer terms together. then the inner then the last

OpenStudy (anonymous):

No thats not right

OpenStudy (anonymous):

I did 2x* 4x= 8x 2x*2=4x 3*4=12 3*2=6

OpenStudy (anonymous):

then you combine like terms 8x + 4x= 12x

OpenStudy (anonymous):

the first numbers you multiplied both have a x. that mean that it will be x^2. so it is actually 8x^2

OpenStudy (anonymous):

Ohh ok

OpenStudy (anonymous):

so that changes everything. Then you have to remember that the 4 and the 3 both have a x too.

OpenStudy (anonymous):

\[2x \times4x=8x ^{2}\]

OpenStudy (anonymous):

\[2x \times-2=-4x\]

OpenStudy (anonymous):

So you have 8x^2 4x 12x 6 correct?

OpenStudy (anonymous):

then combine (add) 4x and 12x?

OpenStudy (anonymous):

\[3x*4x=12x^2 and 3x*-2=-6x\]

OpenStudy (anonymous):

So the final answer is 8x^2+ 16x -6

OpenStudy (anonymous):

yeah thats right :)

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

*high five* haha

OpenStudy (anonymous):

That isnt an answer :(

OpenStudy (anonymous):

8x2+ 8x – 6 6x2 + 13x – 6 6x2 – 5x – 6 6x2 – 13x – 6

OpenStudy (anonymous):

oh we forgot that there are three numbers with x sorry. when we multiply 4x*3x it will be 12x^2 not 12x

OpenStudy (anonymous):

8x^2+ 8x -6 6x^2+ 13x-6 6x^2-5x-6 6x^2-13x-6

OpenStudy (anonymous):

So A? its the only one that is 8x^2

OpenStudy (anonymous):

wait there arent three numbers with x sorry i was confused. yeah its A

OpenStudy (anonymous):

Im not guessing I know its A. I just read the problem wrong. sorry for all of the confusion!

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