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if g(x)=1/x^3, find g'(x)
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@TheSmartOne
@pooja195 , @EclipsedStar
Sorry, I don't know this. Maybe these users can help :) @dan815 @eliassaab @ikram002p @jim_thompson5910 @Loser66
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yes, but i need a derivative of g(x).
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so?? apply n rule then get the answer, dat sit
ok, (x^3)' =?
3x^2, right?
yup, how to get it?
use formula of derivative: lim_(c->0) (g(x+c)-g(x))/c. Is this right?
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OMG, why do you have to use definition? why don't you use theorem?
which theorem? i know only definition
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