5x + y = 6 5x + 3y = -4 The y-coordinate of the solution to the system shown is _____. -5 -1 .5 1
I was thinking maybe I could substitute each number in for y , but that confused me
If you solve the system of equations using elimination... \(\sf ~~~5x + y = 6\\ - \\~~~5x + 3y = -4 \\------- \) Subtract both equations.
um, I may sound stupid but how would I subtract the equations? like regular subtraction?
I got x+2y=10
5x-5x = 0 Just ignore the variable and subtract the 2 numbers and at the end put back the variable.
So to subtract y- 3y Think of it as 1-3 And whatever you get put 'y' right next to it.
So what is \(\sf 1-3=?\)
it would be -2 .. do if 5x-5x becomes 0 I wouldnt have a x variable at all anymore ?
yup the x would go away becaue 0x = 0 = nothing and sine it equals to -2 we add the y back and we get \(\sf -2y\)
so the overall new equation is -2y=10 ? or did I miss something ?
What is \(\sf 6-(-4)=?\) |dw:1426636045220:dw|
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