If y varies inversely with x and y = 3 when x = 4, what is the value of y when x = 2? A.1/6 B.y = 2 C.y = 6 D.y = 12
@jdoe0001 can you help me again?
y = kx this is a direct variation, k being a constant of proportion y = k/x this is an inverse variation. k still being the constant of proportion do you see the difference?
Yeah, the direct variation is the multiply and the inverse is the divide i think?
Yes. The first step is solve for the k. You are given that 3 = k/4 can you solve for k?
0.75 if i divide. 12 if i multiply
What divided by 4 equals 3? That is what the equation is saying.
One of your answers is correct.
i multiply both side by 4 i get 12.
Yes, k is 12. Now we can solve the problem y = 12/2
How to do that?
if i divide 12/2 i get 6y
They have given you the value of x as 2, and you now know k=12 so it is quite easy to solve for y.|dw:1426639427371:dw|
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