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Calculus1
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determine the coordinates of the points on the curve y=tanx between 0 and 2pi where the tangent line is perpendcular to y=-1/2x+3
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@undeadknight26 @Callisto
tanx become secx^2 right?
*head be spinning* Umm...Umm Blue? @aaronq @sleepyjess @dumbcow @Data_LG2 @dan815
@nincompoop
@SithsAndGiggles
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yes, y ' = sec^2 x
Refer to the attachment.
slope perpendicular to -1/2 is 2 set derivative equal to 2 \[\sec^2 x = 2\] \[\sec x = \pm \sqrt{2}\] \[\cos x = \pm \frac{1}{\sqrt{2}}\] \[x = \frac{\pi}{4} + \frac{\pi}{2}k\]
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