how would i graph y=4/5x + 14/5
y = mx+b m is the slope b is the y-intercept
y = mx + b m is rise over run so 4 up and 5 over to the right also on the y axis ( your b) is 14/5 so your y intercept is 2.8 point (0,2.8)
@Austin6i6 so would it look like this?
you can graph the equation by first identifying its intercepts - the y-intercept and the x-inceterpt the y-intercept of an equation of a line in the form of y = mx + b is the b such as the case (format) of your equation the x-intercept of an equation of a line may be solved by making the equation to zero, that is: 0 = 4/5 x + 14/5 then solve for the x
once you have determined the value of the x and the value of the y understand that x intercept's coordinates is in the format of (x, 0) and the y-intercept's coordinates is in the format of (0, y)
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@nincompoop okay that makes a lot more sense thank you!
you're welcome
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