Question

The sum of 3 consecutive integral numbers is 117. Find the numbers.

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Answer 1

let the three numbers be a,a+1.a+2

Answer 2

so the sum of these numbers will be a+a+1+a+2=117

Answer 3

3a=117-3
a=114/3
a=38

Answer 4

so the numbers are 38 ,39,40

Answer 5

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Answer 6

Oh OK. I'm still wondering how did you get the numbers though.

Answer 7

i assumed one number a .

Answer 8

as the other two are integers and also consecutive so they must be a+1 and a+2 respectively

Answer 9

So would any group of numbers that equal 117 qualify for an answer? I'm also confused on what "integral numbers" are.

Answer 10

no only 38 39 and 40 are such numbers whose sum is equal to 117

Answer 11

u know abt integers ?

Answer 12

No i'm not familiar with it.

Answer 13

integeral numbers are number which are not a fraction .a whole number like .......-3,-2,-1,0.1.2,3,..... and so on all are integers

Answer 14

u know abt natural numbers or whole numbers ?

Answer 15

Yes I know what natural and whole numbers are.

Answer 16

ok.integers are like whole numbers bt negative numbers are also included in integers.

Answer 17

all whole numbers are integers

Answer 18

OK i'm starting to get it. Thanks for the help Danish.

Answer 19

welcome.