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Mathematics 16 Online
OpenStudy (anonymous):

help me with question 3 medal and fan

OpenStudy (anonymous):

OpenStudy (anonymous):

@Kchart1234 @BloomLocke367

OpenStudy (anonymous):

@dan815 @AnswerMyQuestions @Centipede

OpenStudy (anonymous):

@inowalst @iGreen @VengefulWave @iSpiffy2wice

OpenStudy (anonymous):

help

OpenStudy (igreen):

Okay, here is our data: 6, 8, 12, 15, 18, 20, 20, 20, 26, 28, 29, 30, 31, 32, 32, 34 Find the Mean and Median, do you know how?

OpenStudy (anonymous):

yes

OpenStudy (igreen):

Okay, tell me what you get.

OpenStudy (anonymous):

k 180 for the mean

OpenStudy (igreen):

I got something different.

OpenStudy (anonymous):

median is 20,26

OpenStudy (igreen):

Yes, those are the two numbers in the middle..but the median is one number..so we have to find the mean of 20 and 26. \(\dfrac{20 + 26}{2}\)

OpenStudy (anonymous):

k

OpenStudy (anonymous):

SO D

OpenStudy (igreen):

?

OpenStudy (igreen):

What did you get for the median?

OpenStudy (igreen):

And D is wrong..

OpenStudy (igreen):

Add 20 + 26 and divide by 2

OpenStudy (anonymous):

23

OpenStudy (igreen):

Yes, so that is the median.

OpenStudy (anonymous):

ok

OpenStudy (igreen):

6, 8, 12, 15, 18, 20, 20, 20, 26, 28, 29, 30, 31, 32, 32, 34 Now, the mean is the sum of all the numbers divided by how many numbers there are. Add up all the numbers and divide by 16.

OpenStudy (anonymous):

i couldn't get it

OpenStudy (anonymous):

can u get the answer for me

OpenStudy (anonymous):

a

OpenStudy (anonymous):

give me a answer and why

OpenStudy (anonymous):

help me with anther pls

OpenStudy (igreen):

The Median of the original data is 23.. The Median for the new data is 26 The Mean of the original data is approximately 22.6 The Mean for the new data is 23

OpenStudy (anonymous):

so which................

OpenStudy (anonymous):

c

OpenStudy (anonymous):

@iGreen

OpenStudy (igreen):

What's 26 - 23?

OpenStudy (anonymous):

can u help me with the other on e

OpenStudy (igreen):

Sure, but don't you want to get this one done first?

OpenStudy (anonymous):

i'm done

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