Help! Please explain how I do this STEP BY STEP! http://prntscr.com/6ial25
@AnswerMyQuestions @iGreen
Cross multiply.
How do I do that with that problem?
\(\dfrac{1}{7} = \dfrac{3}{4x-1}\) \(\dfrac{1}{7} \nearrow \dfrac{3}{4x-1}\) \(\dfrac{1}{7} \searrow \dfrac{3}{4x-1}\) Giving us: (1)(4x - 1) = (7)(3)
1 times anything equals itself. 4x - 1 = (7)(3) Simplify
7*3=21 1*4=4
What is the (7)(3) for
\(\dfrac{1}{7} \nearrow \dfrac{3}{4x-1}\)
Yes, so we have: 4x - 1 = 21 Add 1 to both sides.
Ok so you just do the denominter on the 2nd problem then you do the demoninater on the first problem * the numerater on the second.
Is this something you would do for every problem like this?
Yep
If they're proportions..fractions that equal each other.
So if it equals 21 how would I turn it into a fraction
? Why would we want to do that?
4x - 1 = 21 Solve this
Look at the problem we have to put in a fraction and its 21 right?
No, 21 isn't the answer.. we have to solve that equation.
Add 1 to both sides then divide 4 to both sides.
Wait why do we do that
How would I add 1 to both sides and why do I divide by 4
That's how you solve the equation..we're isolating the variable.
Im sorry I have a really hard time understanding things
4x - 1 = 21 We want to get rid of '1' and '4' to get 'x' by itself. We do the opposite to keep the equation balanced. So since 1 is being subtracted, we add it to both sides.
So how would that be written out?
@igreen help please ^
@confluxepic
@sammixboo
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