Question

MEDAL!!
Solving logarithm equation

Answer 1

u know
\[\log_{x} a - \log_{x} b = \log_{x} (\frac{ a }{ b }) \]

Answer 2

okay ill try to solve it

Answer 3

my first stepp..is that riight??

Answer 4

nah its not..... have a look u have put 2 as exponent of both numerator and denominator.....

Answer 5

oh okay

Answer 6

what do i have to do after? im stuck

Answer 7

\(\bf log{\color{brown}{ (x+5)^2 }}-log(x+5)=log(2)\implies log\left( \cfrac{\cancel{{\color{brown}{ (x+5)^2 }}}}{\cancel{(x+5)}} \right)=log(2)\)

Answer 8

u will have
\[\log_{10} \frac{ (x + 5)^{2} }{ x + 5 } = \log_{10} 2 \]
\[\log_{10} (x + 5) = \log_{10} \]

Answer 9

its
\[\log (x + 5) = \log 2\]

Answer 10

@rishavraj where did you got \[ \log_{10} \]

Answer 11

forget it.....

Answer 12

its clearly hmm log (x + 5) = log 2

Answer 13

@jdoe0001 is my final answer \[\log_{2} \]?

Answer 14

no
u know
\[\log_{x} a = y \]
so \[a = x ^{y}\]

Answer 15

well... so.... where are you at thus far?

Answer 16

the one that you wrote @jdoe0001

Answer 17

\(\bf \bf log{\color{brown}{ (x+5)^2 }}-log(x+5)=log(2)\implies log\left( \cfrac{\cancel{{\color{brown}{ (x+5)^2 }}}}{\cancel{(x+5)}} \right)=log(2)
\\ \quad \\
log(x+5)=log(2)\implies x+5=2\implies x=?\)

Answer 18

3 @jdoe0001

Answer 19

@clamin done???

Answer 20

3? recheck

Answer 21

nah u r wrong...

Answer 22

im stuck

Answer 23

x + 5 = 2
subtract 5 on both sides

Answer 24

i got 3 because i subtract 5 and 2

Answer 25

once both equations are based on log() terms
then we can UNlog them
and then we end up with x+5 = 2

so... that'd be simple enough I'd think

Answer 26

x + 5 = 2
x = 2 - 5
????

Answer 27

\[-\frac{ 2 }{ 5 }\]

Answer 28

hmm ???? u need to subtract
x + 5 = 2
x = 2 - 5
??????why u dividing????

Answer 29

oops my bad its... -3

Answer 30

yup...:))