Will fan and medal:
HELP!! What is an equation of a parabola with the given vertex and focus? vertex: (–2, 5); focus: (–2, 6)

Question

Will fan and medal:
HELP!! What is an equation of a parabola with the given vertex and focus? vertex: (–2, 5); focus: (–2, 6)

campbell_st · Answer

start by drawing a diagram 

|dw:1426734542238:dw|

so the equation is in the form 

$$(y - k)^2 = 4a(x - h)$$

(h, k) is the vertex

a is the focal length ... of the distance between the vetrex and focus

madgirlwithabluebox · Answer

so $$(y-5)^2=4(1)(x+2) $$ ?

rizags · Answer

no, campbell's diagram and equation are in the incorrect form.

madgirlwithabluebox · Answer

well i already submitted it so its cool..could you help me work out the correct answer anyway so i know how to find it next time?

rizags · Answer

ok, so the true equation of a parabola in the form you described, is $$4a(y-k)=(x-h)^2$$

rizags · Answer

yea just plug in everything and thats the equation

rizags · Answer

got it? Medal please