Question

Write the standard equation for the circle that passes through the points:
(-1, 2)
(4, 2)
(- 3, 4)

has to be in x^2 + y^2 + dx + ey + f = 0 form plz help Idk how to do this at all

Answer 1

1+4-d+4e+f=0
16+4+4d+2e+f=0
9+16-3d+4e+f=0

Answer 2

^^^simplified(-d+4e+f=-5) (4d+2e+f=-20) (-3d+4e+f=-25)

Answer 3

solve system of 3 equations
first eliminate one of the variables thus making it a system of 2 equations
then eliminate another variable, leaving a single equation
solve for remaining variable
then use back substitution to obtain other variables

Answer 4

start with "f" first

4d +2e +f = -20
-(-d +4e+f = -5 )
-------------------------
5d -2e = -15

4d +2e +f = -20
-(-3d+4e+f=-25)
-------------------------
7d -2e = 5

Answer 5

now eliminate "e"

5d -2e = -15
-(7d -2e =5)
-----------------
-2d = -20

---> d = 10

Answer 6

okay so how would i find e and f?

Answer 7

substitution