Find the solutions to the system.

Type Equation Remarks
Linear 3x + 5y = -10 A
line with
intercepts
(-, 0) and (0, -2).
Exponential y = -6(3)x This function
lies in quadrants
III and IV.

Question

Find the solutions to the system.

Type                        Equation                    Remarks
Linear                  3x + 5y = -10                A 
                                                            line with
                                                           intercepts
                                                  (-, 0) and (0, -2). 
Exponential            y = -6(3)x       This function
                                                   lies in quadrants
                                                          III and IV.

ellie202000 · Answer

Here is the graph they came up with.
How did they get the graph and the coordinates?
The answers are (-3, -0.2) and (-1.6, -1). How did they come up with that?

solomonzelman · Answer

the second function should be,  $\large\color{black}{ \displaystyle  y=-6(3)^x }$.
the graph they posted is correct.
remark - should include the second quadrant as well.

solomonzelman · Answer

AT FIRST
do you understand how to graph the line, or not?

ellie202000 · Answer

No that's what confusing me the most.

solomonzelman · Answer

put in a y-intercept form
y=mx+b

and plug in any number for x to find the y.
(write your answer in terms of a coordinate (x,y) and do this again to obtain at least 2 (x,y) coordinates.)

Connect the coordinates and graph your line through those coordinates/points
using a ruler.

ellie202000 · Answer

They say I am allowed to use a graphing calculator but I don't know how to use a graphing calculator.

ellie202000 · Answer

But what if you have a problem with an exponent? Like this one:$$Y=-5^{-X}$$$$Y=X+5$$

solomonzelman · Answer

https://www.desmos.com/calculator