can someone help me with graphing the function?
xy+5=0
sketch the graph of the function
@jim_thompson5910
First you need the form y=mx+b...this is the easiest way to do this... for x-y=5: y=-x+5 for y-x=0: y=x+0 in y=mx+b, m is your slope and b is your y intercept...
So when you are graphing these...use your slope and intercept to graph. Start with your intercept. 5 is your first one. and 0 is your second one. (0,5) (0,0) Then use your slope... y=-x+5 has a slope of -1 (your coefficient of x) which is the same as -1/1, so you use rise over run... however in this case you have a negative slope, so instead of going up one, right one... you will go DOWN one, right one.
This site is a good graphing calculator. https://www.desmos.com/calculator
First solve for y xy+5=0 xy+5-5=-5 xy = -5 xy/x = -5/x y = -5/x
Once you have y = -5/x, you plug in any value of x you want (except for x = 0) to get corresponding values of y. Then you will plot the points you get. Draw a curve through the points and keep in mind of the asymptotes
alright thank you so much :)
the link TheSmartOne posted is a good way to check your work
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