Help Please! 2 questions involving quadratics equations, i know how to solve them, but I cannot figure out how to solve these 2 problems. (I have to complete it myself, which I havve NEVER done before. Any guidance would be greatttt!!!) Will post my q's in the comments below, thanks!!!
For the first one: \(x^2-11x+~?\) In completing the square, think of your function as a quadratic: \(ax^2+bx+c=0\).
Therefore, you need to find your `c` value, and in order to do that,you need the `b` value from the quadratic, use the formula:\[c=\left(\frac{b}{2}\right)^2\]
30.25?
d for both
Don't give out answers.
u can simply open the square and then u get ur answer
I'm explaining how to complete the square.
@HARSH123 thank you for the answer, but it is important for me to learn how to work these out. @Jhannybean i'm hoping i'm on the right track here lol
\[x^2-11x+\left(\frac{-11}{4}\right)^2 =\left(\frac{-11}{2}\right)^2\]Now a quick way to simplify the perfect square is to take into account your c value. basically your function always reduces to your b-value/2. This is a rule.\[c=\left(\color{red}{\frac{-11}{2}}\right)^2\]\[x^2-11x+~?=0 \implies \left(x-\color{red}{\left(\frac{b}{2}\right)}\right)^2=c\]
Ohhhhh, @Jhannybean thank you!! I get it (I really do!) thank you! I see how to get the answer now :) thank you for actually showing me how to do it, instead of just blurting out answers at me lol xD
Yoru function always will simplify to (x-(b/2))\(^2\)*
No problem, Try the next one the same way and you can check back with me.
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