Solve the system, using substitution. What is the x coordinate of the solution? x = 2y - 2 and 3x - y = 14 A. 6 B. 4 C. 1 D. 0 E. no solution
replace x with (2y-2) in the 2nd equation
so the answer would be a?
\(x = 2y - 2 \\ 3x - y = 14\implies 3(2y-2) - y = 14 \) solve for y, plug it into one of the equations to find x
4?
yeah, A seems right
A?? not B?
\(3(2y−2)−y=14\\6y-6-y=14\\6y-y-6=14\\5y-6=14\\5y=20\\y=4\) then we plug it back into one of the original equations
god, I hate this site
im lost
so we have \(x = 2y - 2 \\y=4\) \(x=2y-2\\x=2(4)-2\)
do you know how to solve by substitution?
no
there's a solution (x,y) to this system ``` x = 2y - 2 3x - y = 14 ``` solving by substitution involves replacing one of the variables in one equation with part of another equation. basically, we know that x=2y-2 using that we can plug it into the second equation and solve for the y coordinate of the system's solution then we plug the number we get for the y into that same equation and x=8-2=6
Why didnt you just tell me i was right when i wrote A...
because you could have guessed it
I'm sorry for putting in 5 minutes of my time, free of charge, to try and teach you something
Learn to be respectful and grateful
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