Question

Can the fundamental theorem of calculus be used to find Integral((2x^2-x-3)/sqrt(x),x,0,2)

Answer 1

I think the answer would be no, because sqrt(0) is infinity and it would make the function discontinuous across that interval.

Answer 2

some improper integrals converge

Answer 3

this integral converges

Answer 4

$$ \Large \int_0^2 \frac{(2x^2-x-3)}{\sqrt x }~dx $$