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What is the slope of the curve: r=1+2cos(theta) @ (theta)=pi/2
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\[r=1+2\cos(\theta) ;(\theta)=\pi/2\]
first do d derivative
can u?
dr/dtheta = theta -2sin(theta)
\[dr/d \theta = \theta -2\sin(\theta)\]
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simply plug in pi/2 for theta now
easy
\[r=1+2\cos(\theta) ;(\theta)=\pi/2\]Find dr/d(theta). The correct result does not begin with theta.
Hints: What is the derivative of a constant? What is the derivative of the sine function?
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